Question

The probability not getting a sum 2 in a single throw with a pair of dice is 
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Answer 1

$\bold{Answer:}$

Total number of outcomes is 36.

Let E be the event of getting the sum as perfect square.

Number of outcomes favourable to E are 7:

(1,3),(2,2),(3,1),(3,6),(4,5),(5,4),(6,3)

 

Probability of E is number of outcomes favourable to E divided by total number of outcomes that is  $\bold{\frac{7}{36} }$

Hence, the probability of getting the sum as perfect square is  $\bold{\frac{7}{36} }$.

Answer 2

Answer:

the probability of not getting sum of 2 dice thrown is 33/36

Step-by-step explanation:

(0,2)(2,0)(1,1) these are the events occur when sum is 2 out of total 36 events so p= 36-3/36

33/36