the probability of a month of february in a non-leap year having 5 monday is ............... explain
a. 1/5 b.2/7 c.1/7 d.0
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answer is zero,
because in non -leap year, february is of 28 days and every single day comes only 4 times.
because in non -leap year, february is of 28 days and every single day comes only 4 times.
rushabhchauhan9:
thanks all answed my question
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The probability of having 5 mondays is 0
February has 5 mondays only in a leap year.
In a non- leap year february has only 4 mondays
Therefore the probability is 0
In a non leap year no.of days in february = 28 days
n(S) = 28
Let E be the event of getting 5 mondays
n(E) = 0
P(E) = n(E)/n(S)
= 0/28 = 0
February has 5 mondays only in a leap year.
In a non- leap year february has only 4 mondays
Therefore the probability is 0
In a non leap year no.of days in february = 28 days
n(S) = 28
Let E be the event of getting 5 mondays
n(E) = 0
P(E) = n(E)/n(S)
= 0/28 = 0
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