Question

the probability of a non leap year not having 53 Sundays​

Answer 1

The non leap year (ordinary year ) has 52 weeks and 52 Sundays.

There are , 7 days in the week

S = { Sunday , Monday , Tuesday , Wednesday , Thursday , Friday , Saturday}

Therefore, n(S) = 7

Now , suppose A is the event that is gets Sunday

A ={sunday}

n(A) = 1

Now , p(A) = n(A) / n(S ) = 1 / 7

P(A) = 1 / 7

Plzzz tell me if answer is wrong