Question

The probability of a shooter hiting a target is 3/4.How many minimum number of times must he/she fire so that the probability of hitting the target at least once is more than 0.99

Answer 1

Answer:

4

Step-by-step explanation:

probability not to hit out of 1 hit  =1/4 =0.25

probability not to hit out of 2 hit =1/4 x1/4 = 0.0625

probability not to hit out of 3 hit =1/4x1/4x1/4 =0.015625

probability not to hit out of 4  hit =1/4 x1/4x1/x1/4 = 0.00390625  

probability of hitting atleast one = 1 - 0.00390625

                                                      = 0.99609375  greater than 0.99