Question

The probability of an event A occurring is 0.5 and B occurring is 0.3. If
A and B are mutually exclusive events, then find the probability of
neither A nor B occurring

Answer 1

Answer:0.2

Step-by-step explanation:

A and B are mutually exclusive events... P(AΠB)=Φ=0

P(A U B)=P(A)+P(B)-P(AΠB)

=0.5+0.3

=0.8

P(A U B)'=1-P(A U B)

=1-0.8

=0.2

Answer 2

The required probability is 0.2.

Step-by-step explanation:

Since we have given that

Probability of getting an event A = 0.5

Probability of getting an event B = 0.3

Since they are mutually exclusive,

So, P(A∩B) = 0

So, P(A∪B) = P(A)+P(B) - P(A∩B)

P(A∪B) = 0.5+0.3=0.8

So, Probability of neither A nor B is given by

$P(A\cup B)'=1-P(A\cup B)=1-0.8=0.2$

Hence, the required probability is 0.2.

# learn more:

The probability of two events A and B are0.25 and 0.40 respectively. The probability that both A and B occur is 0.15. The probability that neither A nor B occur is _________

https://brainly.in/question/8451482