Question

The probability of drawing a red ball from a beg, containing 6 blue, 5 green and 8 orange ball is
(a) 6/19
(b)5/19
(c)8/19
(d)0​

Answer 1

Given

$\bold{Total \ number \ of \ blue \ balls} = 6$

$\bold{Total \ number \ of \ green \ balls} = 5$

$\bold{Total \ number \ of \ orange \ balls} =8$

$\bold{Total \ number \ of \ balls} = 6+5+8 = 19 \ balls$

To Find

Probability of getting a red ball

$\implies \sf \dfrac{Total \ number \ of \ red \ balls}{Total \ number \ of \ balls}$

$\implies \dfrac{0}{19}$

$\implies 0$

$\boxed{\boxed{\bold{Therefore, \ option \ d) \ = 0 \ is \ the \ answer}}}}}}}$

                                                     

Answer 2

Given :

• No. of Blue ball = 6

• No. of Green ball = 5

• No. of Orange ball = 8

• No. of Red ball = 0

To Find :

• Probability of getting a Red ball

Solution :

Probability = Outcome no. / Total no.

→ 0 / 0 + 6 + 5 + 8

→ 0 / 19

→ 0

Probability of getting a Red ball is 0