the probability of getting 11 when an ordinary die is thrown twice
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Total number of outcome =6
P(getting 11)=0/6
P(getting 11)=0/6
05102004:
Sample space (1, 2, 3, 4, 5, 6)
Therefore probability of getting 11 is 0 (impossible event
That's what I have answered
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0/12 is the probability.
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