Question

the probability of getting 2 heads in toossing 5 coins is​

Answer 1

Answer:

Atleast 2 Heads in 5 Coin Tosses

The ratio of successful events A = 26 to the total number of possible combinations of a sample space S = 32 is the probability of 2 heads in 5 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 2 heads, if a coin is tossed five times or 5 coins tossed together. Users may refer this tree diagram to learn how to find all the possible combinations of sample space for flipping a coin one, two, three or four times.

Solution

Step by step workout

step 1 Find the total possible events of sample space S

S = {HHHHH, HHHHT, HHHTH, HHHTT, HHTHH, HHTHT, HHTTH, HHTTT, HTHHH, HTHHT, HTHTH, HTHTT, HTTHH, HTTHT, HTTTH, HTTTT, THHHH, THHHT, THHTH, THHTT, THTHH, THTHT, THTTH, THTTT, TTHHH, TTHHT, TTHTH, TTHTT, TTTHH, TTTHT, TTTTH, TTTTT}

S = 32

step 2 Find the expected or successful events A

A = {HHHHH, HHHHT, HHHTH, HHHTT, HHTHH, HHTHT, HHTTH, HHTTT, HTHHH, HTHHT, HTHTH, HTHTT, HTTHH, HTTHT, HTTTH, THHHH, THHHT, THHTH, THHTT, THTHH, THTHT, THTTH, TTHHH, TTHHT, TTHTH, TTTHH}

A = 26

step 3 Find the probability

P(A) =Successful Events

Total Events of Sample Space

=26

32

= 0.81

P(A) = 0.81

0.81 is the probability of getting 2 Heads in 5 tosses.

Here is your answer.

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Answer 2

Answer:

number of sample space = 25

n(S)= 25

E= getting 2 heads

n(E) = 5

P(E) = n(E)/n(S)

P(E) = 5 / 25

P(E) = 1 / 5