Question

the probability of getting 53 fridays in a leap year is ​

Answer 1

What is the probability of 53 Fridays in a leap year?

A leap year has 366 days. If we take the weeks, it has 52. Altogether, 52 weeks and 2 days. So, in all possibility, we are going to have 52 Fridays. The case left is of the remaining 2 days.

Now, the two days in order could be

Thursday & Friday

Friday & Saturday

There are in total 7 possibilities of these two days as the 1st day could be any one of the seven days and consequently the 2nd would be the adjacent day.

So, the probability of 53 Fridays turns out to be 2/7

Answer 2

$\bf{\huge{SOLUTION:-}}$

In a year,

7 × 52 = 364 (7 days, 52 weeks)

Hence,

We have 2 days left,

Those days could be

{Mon,Tue ; Tue,Wed ; Wed;Thu ; Thu,Fri ; Fri;Sat ; Sat,Sun ; Sun,Mon}

Here, Friday comes twice,

Hence,

The probability is $\frac{2}{7}$