Question

The probability of getting a sum greater than 8 in single throw of two dice

Answer 1

1/ 12

as you can only one 8 and if you throw two dice its total will be 12 6+6

Answer 2

$s ={(11)(12)(13)(14)(15)(16)(21)(22)(23)(24)(25)(26)(31)(32)(33)(34)(35)(36)(41)(42)(43)(44)(45)(46)(51)(52)(53)(54)(55)(56)(61)(62)(63)(64)(65)(66)$

n (S)= 36

event A =

${(45)(46)(36)(54)(55)(56)(63)(64)(65)(66)}$

therefore n (A ) = 10

P (A)= n (A)÷n (S)

=10 ÷36

=5 ÷18