Question

The probability of getting a total of 7 atleast once in three tosses of a pair of fair dice is

Answer 1

Answer:

Tossing a pair of fair dice is an independent trial.

Pr( Total of 7 in a toss)= 6/36= 1/6

Let X be the the occurence of a total of 7:

Pr(X≥1)=1-Pr(X=0)=$1-(\frac{5}{6})^3=0.42 (2 d.p.) =\frac{96}{216}$

Recognising that it is a binomial distribution is the key to finding the probability.

Hope this helps :)

Step-by-step explanation: