Question

the probability of getting an even number when a fair dice is rolled once.....?​

Answer 1

Step-by-step explanation:

$no \: of \: possible \: outcomes = 3 \\ totl \: no \: of \: outcomes = 6 \\ p(getting \: even \: number \: when \: dice \: is \: rolled) = \frac{no \: of \: possible \: outcomes}{total \: no \: of \: outcomes} \\ = > \frac{3}{6} \\ = > \frac{1}{2}$

hence the probability is 1/2

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