Math, asked by Anamika1111, 1 year ago

the probability of getting neither an ace nor a king from a pack of well shuffled 52 card is

Answers

Answered by nms
127
first find the probability of getting ace and king card
that is.
p = favourable outcome/total outcome
=(4+4)/52
=8/52
=2/13
now probability of not getting ace and king us 1-2/13
=11/13

pls mark it as brainliest.
Answered by pinquancaro
29

Answer:

The probability that the card drawn is neither an ace nor a king \frac{11}{13}

Step-by-step explanation:

To find : The probability of getting neither an ace nor a king from a pack of well shuffled 52 card?

Solution :

A deck of playing cards consists of 52 cards.

13 cards of heart

13 cards of diamond

13 cards of spades

13 cards of club

13 cards in each suit are Ace, king ,queen, Jack, 10, 9,8,7,6, 5, 4, 3 and 2.

King, queen,and jack are called face cards.

Favorable outcomes = four cards are of Ace & 4 cards are of king = 8

Total number of favorable outcomes = 52-8= 44

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcome}}

\text{Probability}=\frac{44}{52}

\text{Probability}=\frac{11}{13}

Therefore, The probability that the card drawn is neither an ace nor a king \frac{11}{13}

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