the probability of having 53 Fridays in a leap year is .solve it
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1 year = 365 days
A leap year has 366 days
A year has 52 weeks.
Hence there will be 52 Sundays for sure.
52 weeks =  days
366 – 364 =2 days
In a leap year there will be 52 Sundays and 2 days will be left.
These 2 days can be:
Sunday, Monday
Monday, Tuesday
Tuesday, Wednesday
Wednesday, Thursday
Thursday, Friday
Friday, Saturday
Saturday, Sunday
Of these total 7 outcomes, the favourable outcomes are 2.
Hence the probability of getting 53 days 
A leap year has 366 days
A year has 52 weeks.
Hence there will be 52 Sundays for sure.
52 weeks =  days
366 – 364 =2 days
In a leap year there will be 52 Sundays and 2 days will be left.
These 2 days can be:
Sunday, Monday
Monday, Tuesday
Tuesday, Wednesday
Wednesday, Thursday
Thursday, Friday
Friday, Saturday
Saturday, Sunday
Of these total 7 outcomes, the favourable outcomes are 2.
Hence the probability of getting 53 days 
Hephz:
hence the Probabliry is 2/7
yes
Answered by
1
1 year = 365 days
A leap year has 366 days
A year has 52 weeks.
Hence there will be 52 Sundays for sure.
52 weeks = 364 days
366 – 364 =2 days
In a leap year there will be 52 Sundays and 2 days will be left.
These 2 days can be:
Sunday, Monday
Monday, Tuesday
Tuesday, Wednesday
Wednesday, Thursday
Thursday, Friday
Friday, Saturday
Saturday, Sunday
Of these total 7 outcomes, the favourable outcomes are 2.
Hence the probability of getting 53 days is 2/7
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