Math, asked by kiranpanchal, 1 year ago

the probability of having 53 Fridays in a leap year is .solve it

Answers

Answered by Hephz
1
1 year = 365 days

A leap year has 366 days

A year has 52 weeks.

Hence there will be 52 Sundays for sure.

52 weeks =  days

366 – 364 =2 days

In a leap year there will be 52 Sundays and 2 days will be left.

These 2 days can be:

Sunday, Monday
Monday, Tuesday
Tuesday, Wednesday
Wednesday, Thursday
Thursday, Friday
Friday, Saturday
Saturday, Sunday

Of these total 7 outcomes, the favourable outcomes are 2.

Hence the probability of getting 53 days 
                     

Hephz: hence the Probabliry is 2/7
Ajwad8102: yes
Answered by Ajwad8102
1

1 year = 365 days

A leap year has 366 days

A year has 52 weeks.

Hence there will be 52 Sundays for sure.

52 weeks = 364 days

366 – 364 =2 days

In a leap year there will be 52 Sundays and 2 days will be left.

These 2 days can be:

Sunday, Monday
Monday, Tuesday
Tuesday, Wednesday
Wednesday, Thursday
Thursday, Friday
Friday, Saturday
Saturday, Sunday

Of these total 7 outcomes, the favourable outcomes are 2.

Hence the probability of getting 53 days is 2/7
                                                                               
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