Question

The probability of hitting a target is 0.1 and 10 shots are fired independently , what is the probability that the target will be hit at least once

Answer 1

Answer:

1

Step-by-step explanation:

probability is 0.1

total number of shots fired

let number of shots hit = x

$\frac{x}{10} = 0.1\\\frac{x}{10} = \frac{1}{10} \\x = 1$

Answer 2

Answer:

The probability of hitting a target in any shot is 0.2. If 10 shots are fired, find the probability that the target will be hit at least twice.

The probability of hitting a target in any shot is 0.2

The probability of not  hitting a target in any shot is 1-0.2 = 0.8

probability that the target will be hit at least twice. = 1 - Hit once - Hit never

Probability of Hit once = 0.2 * (0.8)⁹

Probability of Hit Never = (0.8)¹⁰

probability that the target will be hit at least twice = 1 - 0.2 * (0.8)⁹ - (0.8)¹⁰

= 1 -  (0.8)⁹(0.2 + 0.8)

= 1  - (0.8)⁹

= 0.865782272