Question

the probability of not getting diublets in a single throw with pair of dice is​

Answer 1

Given :

single throw with pair of dice

To Find :

probability of not getting doublets

Solution:

A dice has 6 possible out comes = { 1 , 2 , 3 ,4 , 5 ,6 }

pair of dice is thrown

Hence possible outcomes = 6 x 6 = 36

Doublet { (1 , 1) , ( 2 , 2) , ( 3 , 3) , ( 4 , 4) , ( 5 , 5) , ( 6 6) }

6 possible doublets

not doublets = 36 - 6 = 30

probability of not getting doublets = 30/36

30/36= 5/6