The probability of selecting a red ball at random from a jar that contains only red, blue
and orange balls is 1/4. The probability of selecting a blue ball at random from the same
jar 1/3. If the jar contains 10 orange balls, find the total number of balls in the jar.
Answers
Answered by
977
We know,
P(getting red ball) = 1/4
P(getting blue ball) = 1/3
Let the no. of balls = x
Therefore, P(getting orange ball) = 10/x
We know,
P(getting red ball) + P(getting blue ball) + P(getting orange ball) = 1
⇒1/4 + 1/3 + 10/x = 1
⇒10/x = 1 -1/4 -1/3
⇒10/x = 1 - 7/12
⇒10/x = 5/12
⇒10 * 12 = 5 * x
⇒x = 24
Therefore, the no. of balls = x
= 24
P(getting red ball) = 1/4
P(getting blue ball) = 1/3
Let the no. of balls = x
Therefore, P(getting orange ball) = 10/x
We know,
P(getting red ball) + P(getting blue ball) + P(getting orange ball) = 1
⇒1/4 + 1/3 + 10/x = 1
⇒10/x = 1 -1/4 -1/3
⇒10/x = 1 - 7/12
⇒10/x = 5/12
⇒10 * 12 = 5 * x
⇒x = 24
Therefore, the no. of balls = x
= 24
Answered by
93
the question is to find the total number of balls in the bag.
the total number of balls is equal to number of red balls + blue + Orange balls .
probability of getting a red ball is 1/4
probability of selecting a blue ball is 1/3
the number of orange balls is 10.
so , 10 + r + b is equal to x .
10 /x = 1 - 1/4 - 1/3
10/ x = 5 / 12
120 = 5y
=> *y = 24*
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