the probability of selecting a rotten apple randomly from a heap of 900 apples is 0.18. what is the number of rotten apples in the Heap ?
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Answered by
24
total no apples =900
n(s)=900
n(p)=0.18
n(a)=?
n(p)=n(a)/n(s)
0.18=n(a)/900
so,n(a)=0.18*900=162
therefore total no of rotten apples=162
(plz mark as branliest answer if you like it)
thank you
n(s)=900
n(p)=0.18
n(a)=?
n(p)=n(a)/n(s)
0.18=n(a)/900
so,n(a)=0.18*900=162
therefore total no of rotten apples=162
(plz mark as branliest answer if you like it)
thank you
yegavintinithyasri:
162
Answered by
7
P(E) =
Favourable outcome / Total Outcomes
Thus,
18/100 = x/900
Therefore, 18=x/9
X = 18 x 9 = 162 rotten apples
Favourable outcome / Total Outcomes
Thus,
18/100 = x/900
Therefore, 18=x/9
X = 18 x 9 = 162 rotten apples
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