The probability of selecting a rotten apple randomly from a heap of 900 apple is 0.18.what is the no.of rotten apple in the heap
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Total number of apples=900
P(E) of selecting a rotten apple=0.18
no. of rotten apple=?
We know that-
P(E)= No. of favourable apples/ Total number of apples
0.18= No. of favourable apples/900
No. of favourable apples=900×0.18
No. of favourable apples=162
So, answer is 162....
P(E) of selecting a rotten apple=0.18
no. of rotten apple=?
We know that-
P(E)= No. of favourable apples/ Total number of apples
0.18= No. of favourable apples/900
No. of favourable apples=900×0.18
No. of favourable apples=162
So, answer is 162....
Answered by
1
total number of apple =900
probability of rotten apple =0.18
let no. of rotten apple be X.
than,
X/900=0.18
X=900*0.18
X=162.
probability of rotten apple =0.18
let no. of rotten apple be X.
than,
X/900=0.18
X=900*0.18
X=162.
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