The probability of student missing a surprise test is 2/9. If
a student gets absent
twice, find the probability of her
missing at least one surprise test.
779
19/21
32/81
49/81
Answers
Answered by
0
Step-by-step explanation:
We know that
P(ϵ)+P(ϵ)=1
P(ϵ)= Event ϵ occurs
P(ϵ)= Event does not occurs
P (miss. no tests) =P (no test on day 1 and no test on day 2)
=P (no test on day 1)×P (no test on day 2)
=54×54
=2516
So, P (miss at least 1 test) =1−2516
=2525−16
=259
Hence, this is the answer.
Answered by
0
Answer:
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Step-by-step explanation:
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