the probability of throwing more than 5 in a single throw of an ordinary die is:
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Suppose the ordinary die is unbiased, i.e probability of getting any of 1, 2, 3, 4, 5, 6 in a single throw is 1/6. ( since, a die contains numbers from 1 to 6 and every single number has the same probability of come out in the draw.)
Now our objective is to find the probability of throwing more than 5 in a single throw of an ordinary dice. So,
probability = number s more than 5/ total number of the dice
= 1/6
Answer: 1/6.
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