Question

The probability of winning a game is 'x/3'. If the probability of losing the game is 8x/3 then X=​

Answer 1

Step-by-step explanation:

Given :-

The probability of winning a game is 'x/3' and the probability of losing the game is 8x/3.

To find :-

Find the value if X ?

Solution:-

Given that

The probability of winning a game = 'X/3'

Let the winning the game be an event W then the probability of winning game is P(W) = X/3

and

The probability of losing the game is 8x/3.

Let the losing the game be an event L then the probability of losing game is P(L) = 8X/3

We know that

IF E is an event then P(E) + P(not E) = 1

We have,

P(W) + P(L) = 1

=> (X/3) + (8X/3) = 1

LCM = 3

=> (X+8X)/3 = 1

=> 9X/3 = 1

=> 3X = 1

=> X = 1/3

Therefore, X = 1/3

Answer:-

The value of X for the given problem is 1/3

Used formulae:-

→IF E is an event then P(E) + P(not E) = 1

→ The sum of all probabilities of all events in a random experiment is equal to 1

Answer 2

P(W) = x/3

P(L) = 8x/3

By using, P(E) + P(not E) = 1

here, E is Event.

P(W) + P(L) = 1

x/3 + 8x/3 = 1

9x/3 = 1

x = 1/3

Value of x is ⅓