The probability that a man hitting a target is 1/3. If he fires 6 times, find the probability that he fires (i) at most 5 times (ii) exactly once (iii) at least two times.
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Step-by-step explanation:
(i)at most 5 times
no. of favorable outcomes =5
total number of favorable outcomes =6
P(E)=5/6
(ii)no. of favorable outcomes=1
total number of favorable outcomes =6
P(E)=1/6
(iii)at least 2
no.of favorable outcomes =6
total number of possible outcomes =6
P(E)=6/6
=1
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