Question

the probability that a new car will get ab award for its design is 0.25 the probability that it will get an award far efficient of fuel is 0.35 and the probability that it will get both the awards is 0.15 find the probability that it will get at least one of the two awards and it will get only one of the awards ​

Answer 1

$\huge\pink{Answer}$

Probability of winning award for design,

P(0)=0.23

Probability of winning award for fuel efficiency

P(E)=0.35

Probability of winning both award

=0.15=P(D∩E)

P(D)+ P(E)= P(D∪ E)+ P(D∩ E)

P(D∪ E)= P(D)+ P(E)− P(D∩ E)

= 0.25+ 0.35− 0.15

= 0.45

Probability of winning one award

=0.45

Probability that it will get only one of them

=P(D1∩E)+P(D∩E 1

= P(D)− P(D∩ E)+ P(E)− P(D∩ E)

= 0.25+ 0.35− 2(0.45)

= 0.3

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