Question

The probability that a non leap year selected at random will contain 53 sundays is
(A)1/7
(B)2/7
(C)3/7
(D)5/7
PLEASE EXPLAIN ALSO............
THE ONE WHO WILL EXPLAIN WILL BE MARKED BRAINLIEST...​

Answer 1

Answer:

1/7

Step-by-step explanation:

Non leap year=365 days=52 weeks and 1 day

So Total outcomes for remaining 1 day=7

(Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,

Saturday)

Favourable outcome=1 (Sunday)

Probability=1/7

Answer 2

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Correct option: (A)

A non-leap year has 365 days.

365 days = 52 weeks + 1 day

Since 52 weeks = 52 x 7 = 364 days

Hence there will be 52 Sundays in a year.

This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, or Sunday.

Out of these total 7 outcomes, the number of favourable outcomes is 1.

Hence, the probability of getting 53 Sundays = 1 / 7

Hope it's Helpful.....:)