the probability that a non leap year will have 53 fridays and 53 saturdays is
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No of weeks in a year=365/7
Weeks=52 Days left=1
There are 52 Friday's and Saturday's guaranteed in a year, so there is 1 Friday and 1 Saturday left.
But it is impossible that both a Friday and a Saturday will occur in the extra 1 one day.
So, required probability=0
Weeks=52 Days left=1
There are 52 Friday's and Saturday's guaranteed in a year, so there is 1 Friday and 1 Saturday left.
But it is impossible that both a Friday and a Saturday will occur in the extra 1 one day.
So, required probability=0
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