The probability that a pen manufactured by a company will be defective is 1/10. If 12 such pens are manufactured, find the probability that
Answers
Probability that Exactly two will be defective is about 0.23
Probability that at least two will be defective is about 0.341
Given:
- Probability of defective pen = 1/10
- 12 Such Pens manufactured
To Find:
- Probability that
- (i) exactly two will be defective
- (ii) at least two will be defective
Solution:
P(x) = ⁿCₓpˣ(1-p)ⁿ⁻ˣ
n = 12
p = 1/10
1 - p = 1- 1/10 = 9/10
Step 1:
Probability that Exactly two will be defective P(2)
P(2) = ¹²C₂(1/10)²(9/10)¹²⁻²
P(2) = 66 * 9¹⁰ / 10¹²
P(2) ≈ 0.23
Step 2:
Probability that at least two will be defective 1 - P(0) - P(1)
P(0) = ¹²C₀(1/10)⁰(9/10)¹²⁻⁰
P(1) = ¹²C₁(1/10)¹(9/10)¹²⁻¹
1 - P(0) - P(1) ≈ 0.341
Probability that Exactly two will be defective is about 0.23
Probability that at least two will be defective is about 0.341
( Although your Question is Incomplete , probably you are referring to the below Question)
(i) exactly two will be defective (ii) at least two will be defective
https://brainly.in/question/39342899