Question

• The probability that a person can hit a target is 3/5 and the
probability that another person can hit the same target is 2/5. But
the first person can fire 8 shots in the time and second person fires 10
shots. They fire together. What is the probability that the second
person shoots the target?​

Answer 1

Step-by-step explanation:

The probability that a person can hit a target is 3/5 and the

probability that another person can hit the same target is 2/5. But

the first person can fire 8 shots in the time and second person fires 10

shots. They fire together. What is the probability that the second

person shoots the target?

Answer 2

Answer:

Step-by-step explanation:

The second person fires 10 shots in the same time as the first person fires 8 shots.

Therefore , the odds in favour of the second person are 10 : 8 .

The probability that the second person hits the target is 2/5 and the probability that the first person hits the target is 3/5.

So , the odds in favour of the second person are 10 x 2/5 : 8 x 3/5 .

i.e.  20 : 24  or  5 : 6 .

Therefore , the probability that the second person hits the target is 5 ÷ ( 5 + 6 )  =  5/11  Answer.