The probability that a ticketless traveler is caught during a trip is 0.1. if the traveler makes 4 trips , the probability that he/she will be caught during at least one of the trips is:
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ans is 0.025
as probability= favourable case/ total case
= 0.1/4
= 0.025
as probability= favourable case/ total case
= 0.1/4
= 0.025
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