Question

The probability that a two digit number
selected at random will be a multiple of 3
and not a multiple of '5' is
(b) 4/15

(a) 2/15
(c) 7/15
(d) 4/30​

Answer 1

Answer:

ANSWER

⇒ Total number of two digit number =90

⇒ Total number of two digit number which is divisible by 3=30

Out of this there are 6 numbers divisible by 15 (15,30,45,60,75,90) which are also divisible by 5.

⇒ Total two digit number which are divisible by 3 but not 5=30−6=24

⇒ Required probability =

$⇒ Required \: probability = \frac{24}{90 } = \dfrac{4}{15}$

$option \: b \: \dfrac{4}{15} \: is \: the \: answer$

Answer 2

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ʜᴏᴘᴇ ʜᴇʟᴘs ᴜ

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