Question

The probability that a two digit number selected at random will be a multiple of 3 and not a multiple of '5' is (b) 4/15 (a) 2/15 (c) 7/15 (d) 4/30​

Answer 1

Answer:

ANSWER

⇒ Total number of two digit number =90

⇒ Total number of two digit number which is divisible by 3=30

Out of this there are 6 numbers divisible by 15 (15,30,45,60,75,90) which are also divisible by 5.

⇒ Total two digit number which are divisible by 3 but not 5=30−6=24

⇒ Required probability =

$⇒ Required \: probability = \frac{24}{90 } = \dfrac{4}{15}$

$option \: b \: \dfrac{4}{15} \: is \: the \: answer$

hope it helps you........❤️❤️

Answer 2

Answer:

Option b. is correct ...........