Question

The probability that an Accountant's job applicant has a B. Com. Degree is0.85, that he is a CA is 0.30 and that he is both B. Com. and CA is 0.25 out of 500 applicants, how many would be B. Com. or CA?

Answer 1

basic sets problem. hope it helps

Answer 2

The number of applicants that would be B. Com or CA is 450.

Given:

Probability of B. Com degree= 0.85

Probability of CA= 0.30

Probability of both B. Com and CA= 0.25

Total applicants= 500

To Find:

The total no. of applicants with a B. Com degree or CA

Solution:

Let a B. Com degree be denoted by B and a CA degree be denoted by C.

So, according to the question

P(B)= 0.85; P(C)= 0.30; P(B∩C)=0.25

Therefore,

The probability that the applicant has either B. Com or CA,

P(B∪C)= P(B) + P(C) - P(B∩C)= 0.85+ 0.30- 0.25= 0.90

So,

The no. of applicants with B. Com or CA will be,

= N x P(B∪C)= 500 x 0.90= 450

Therefore, 450 applicants would be B. Com or CA.

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