Question

The probability that I will go sailing today AND the fair six-sided die will come up even on the next roll is .3.3.
If these events are independent, what is the probability that I will go sailing today?

Answer 1

Hence the probability is 0.6

Step-by-step explanation:

• Probability that I will go for sailing =  P(A)
• Probability of a die to come up on an even number = P(B)

Now,

P(A and B) = 0.3

It is known to us that the probability of a die to land with an even number on its side up =

Moreover, we are given with the fact that both P(A) and P(B) are independent.

P(A and B) = P(A) × P(B)

⇒ 0.3 = P(A) × 0.5

⇒ P(A) =  = 0.6

Thus the probability that I will go sailing today = 0.6

Answer 2

Answer:

Hence the probability is 0.6

Step-by-step explanation:

Probability that I will go for sailing =  P(A)

Probability of a die to come up on an even number = P(B)

Now,

P(A and B) = 0.3

It is known to us that the probability of a die to land with an even number on its side up =

Moreover, we are given with the fact that both P(A) and P(B) are independent.

P(A and B) = P(A) × P(B)

⇒ 0.3 = P(A) × 0.5

⇒ P(A) =  = 0.6

Thus the probability that I will go sailing today = 0.6

Step-by-step explanation:

Hope this answer will help you.✌️