Question

The probability that I will go sailing today AND the fair six-sided die will come up even on the next roll is .3.. If these events are independent, what is the probability that I will go sailing today?

Answer 1

Let us consider P(A) to be the probability for the fact that I will go for sailing today

Likewise, P(B) will be the probability of a die to come up on an even number in the next roll.

Now, according to the question,

P(A and B) = 0.3

It is known to us that the probability of a die to land with an even number on its side up = $\frac{3}{6} = \frac{1}{2} = 0.5$

Moreover, we are given with the fact that both P(A) and P(B) are independent.

∴ P(A and B) = P(A) × P(B)

⇒ 0.3 = P(A) × 0.5

⇒ P(A) = $\frac{0.3}{0.5}$ = 0.6

Ans) The probability that I will go sailing today = 0.6

Answer 2

The probability is 0.6

Step-by-step explanation:

• Probability for going for sailing = P(A)
• Probability of a die to come up = P(B)

Now as we are given that:

P(A and B) = 0.3

We know that the probability of a die to land with an even number on its side up = 3 ÷ 6 = 1 ÷ 2 = 0.5

We are given that both P(A) and P(B) does not depend on each other.

P(A & B) = P(A) x P(B)

0.3 = P(A) x 0.5

P(A) = 0.6

Hence he probability is = 0.6