The probability that in a year of 22nd century chosen at random there will be 53 sundays is
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Answered by
20
we all know that there is one leap year in 4 years so it's probability is 25/100 is 1/4
and 53 Sunday in leap is 1/4×2/7 is 2/28
similarly probability of 53 Sunday in non leap is is 75/100×1/7 is 3/28 then probability of 53 Sunday in 22 century is 2/28+3/28 is 5/28
and 53 Sunday in leap is 1/4×2/7 is 2/28
similarly probability of 53 Sunday in non leap is is 75/100×1/7 is 3/28 then probability of 53 Sunday in 22 century is 2/28+3/28 is 5/28
Answered by
3
probability that in a year of 22nd century chosen at random there will be 53 sundays = 31/175
Step-by-step explanation:
22nd century
2101 to 2200
Total Year = 100
Leap Years = 2104 to 2196
= 24 Leap Years
100 - 24 = 76 Non - leap Years
Leap year has 366 Days (52 * 7 + 2) hence Probbaility of sunday = 2/7
Non-Leap Year has 365 Days (52 * 7 + 1) hence Probbaility of sunday = 1/7
probability that in a year of 22nd century chosen at random there will be 53 sundays = (24/100)(2/7) + (76/100)(1/7)
= (48 + 76)/700
= 124/700
= 31/175
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