The probability that machine A will be performing a usual function is 5 years' time is (1/4), while the probability that machine B will still be operating usefully at the end of same period is (1/3). Find the probability that in five years' time a. Both machines will be performing a usual function.
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The answer is 1/12
Given:
Let E₁ and E₂ be events defined as:
E₁ the machine A will be performing a usual function
E₂ the machine B will be performing a usual function
P (E₁) = 1/4
P (E₂) = 1/3
To Find:
The probability that in five years
Both machines will be performing a usual function.
Solution:
The events E₁ and are E₂ independent events.
Events Ē1 and Ē2 will also be independent events.
P(both machines will be performing a usual function)
= P (E ∩ F) = P(E) × P (F)
= 1/4 × 1/3
= 1/12
The probability that in five years Both machines will be performing a usual function = 1/12.
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