Question

the probability that Sachin will score a century in next match is 0.7 Find the probability that he will not score a century​

Answer 1

Probability that Sachin scores a century is 0.4.

Probability that Sachin scores a century is 0.4.In four matches, the probability that he scores at least 3 centuries is given by

Probability that Sachin scores a century is 0.4.In four matches, the probability that he scores at least 3 centuries is given by(Let X denote the number of centuries scored by him)

Probability that Sachin scores a century is 0.4.In four matches, the probability that he scores at least 3 centuries is given by(Let X denote the number of centuries scored by him)P(X=3)+P(X=4)

Probability that Sachin scores a century is 0.4.In four matches, the probability that he scores at least 3 centuries is given by(Let X denote the number of centuries scored by him)P(X=3)+P(X=4) (43)×(0.4)3×(0.6)+

Probability that Sachin scores a century is 0.4.In four matches, the probability that he scores at least 3 centuries is given by(Let X denote the number of centuries scored by him)P(X=3)+P(X=4) (43)×(0.4)3×(0.6)+ (44)(0.4)4≈17

Probability that Sachin scores a century is 0.4.In four matches, the probability that he scores at least 3 centuries is given by(Let X denote the number of centuries scored by him)P(X=3)+P(X=4) (43)×(0.4)3×(0.6)+ (44)(0.4)4≈17 Not good enough. Let's try it with 5 matches.

Probability that Sachin scores a century is 0.4.In four matches, the probability that he scores at least 3 centuries is given by(Let X denote the number of centuries scored by him)P(X=3)+P(X=4) (43)×(0.4)3×(0.6)+ (44)(0.4)4≈17 Not good enough. Let's try it with 5 matches.The probability that he scores at least 3 centuries in five matches is the sum of the probabilities of him scoring three, four or five centuries.

Probability that Sachin scores a century is 0.4.In four matches, the probability that he scores at least 3 centuries is given by(Let X denote the number of centuries scored by him)P(X=3)+P(X=4) (43)×(0.4)3×(0.6)+ (44)(0.4)4≈17 Not good enough. Let's try it with 5 matches.The probability that he scores at least 3 centuries in five matches is the sum of the probabilities of him scoring three, four or five centuries.P(X=3)+P(X=4)+P(X=5)

Probability that Sachin scores a century is 0.4.In four matches, the probability that he scores at least 3 centuries is given by(Let X denote the number of centuries scored by him)P(X=3)+P(X=4) (43)×(0.4)3×(0.6)+ (44)(0.4)4≈17 Not good enough. Let's try it with 5 matches.The probability that he scores at least 3 centuries in five matches is the sum of the probabilities of him scoring three, four or five centuries.P(X=3)+P(X=4)+P(X=5) (53)×(0.4)3×(0.6)2+

Probability that Sachin scores a century is 0.4.In four matches, the probability that he scores at least 3 centuries is given by(Let X denote the number of centuries scored by him)P(X=3)+P(X=4) (43)×(0.4)3×(0.6)+ (44)(0.4)4≈17 Not good enough. Let's try it with 5 matches.The probability that he scores at least 3 centuries in five matches is the sum of the probabilities of him scoring three, four or five centuries.P(X=3)+P(X=4)+P(X=5) (53)×(0.4)3×(0.6)2+ (54)×(0.4)4×(0.6)+

Probability that Sachin scores a century is 0.4.In four matches, the probability that he scores at least 3 centuries is given by(Let X denote the number of centuries scored by him)P(X=3)+P(X=4) (43)×(0.4)3×(0.6)+ (44)(0.4)4≈17 Not good enough. Let's try it with 5 matches.The probability that he scores at least 3 centuries in five matches is the sum of the probabilities of him scoring three, four or five centuries.P(X=3)+P(X=4)+P(X=5) (53)×(0.4)3×(0.6)2+ (54)×(0.4)4×(0.6)+ (55)(0.4)5≈31

Probability that Sachin scores a century is 0.4.In four matches, the probability that he scores at least 3 centuries is given by(Let X denote the number of centuries scored by him)P(X=3)+P(X=4) (43)×(0.4)3×(0.6)+ (44)(0.4)4≈17 Not good enough. Let's try it with 5 matches.The probability that he scores at least 3 centuries in five matches is the sum of the probabilities of him scoring three, four or five centuries.P(X=3)+P(X=4)+P(X=5) (53)×(0.4)3×(0.6)2+ (54)×(0.4)4×(0.6)+ (55)(0.4)5≈31 So the answer is 5.

Answer 2

Question:

The probability that Sachin will score a century in next match is 0.7. Find the probability that he will not score a century.

Given:

• The probability that Sachin will score a century in next match is 0.7.

To Find:

• The probability that he will not score a century.

Formula to be used:

$\sf{P(A)=+P(Ā)=1}$

Where,

• P(A)=Favourable elementary event.
• P(Ā)=Negative of an Event.

Solution:

$\rightarrow\mathsf{P(A)+P(Ā)=1}$

We know, that Probability that Sachin will score a century is 0.7.

$\rightarrow\mathsf{0.7+P(Ā)=1}$

$\rightarrow\mathsf{P(Ā)=1-0.7}$

$\rightarrow\mathsf{P(Ā)=0.3}$

Hence, the probability that Sachin wouldn't score a century is 0.3.

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