The probability that that a person will get a painting contract is 3/5 and the probability that he will not get a plumbing contract is 5/7 .If the probability of getting atleast 1 contract is 2/3.Then find the probability that he will get both the contract.
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P(E)= 3/5
P(F) = 1-5/7= 2/7
P(E intersection F) = 2/5 = probability of getting atleast one contract
P(E union F) = probability of getting both the contracts = P(E) + P(F) - P(E intersection F)
= 3/5 + 2/7 - 2/3
= 23/105
Thankyou
P(F) = 1-5/7= 2/7
P(E intersection F) = 2/5 = probability of getting atleast one contract
P(E union F) = probability of getting both the contracts = P(E) + P(F) - P(E intersection F)
= 3/5 + 2/7 - 2/3
= 23/105
Thankyou
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