Math, asked by dharakasaudhan56, 10 months ago

the probability that two friends have different birthday (non leap year).​

Answers

Answered by abitha2206
4

Answer:364/365

Step-by-step explanation:

total number of days n(s)= 365

we know that two different friend birthday was same on 1 day in a year

so 365-1= 364 days are different for each friend

so, n(E)=364

therefore p(E)= n(E)/n(S)

= 364/365

Similar questions