Question

The probability to have exactly 52 Fridays in a non -leap year
is
a) 6/7
b) 1/7
c) 5/7
d) 2/7
​

Answer 1

Answer:

Ordinary year contains 365 days

∴

52

complete weeks and one day .

Possibilities for this one day are:

{Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday}

Total possibilities =

7

favorable cases = 1

∴ probability = 1/7

So option B) 1/7 is your answer !!

Step-by-step explanation:

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Hope it helps you !!

Answer 2

Answer:

The probability to have 52 Fridays in a non -leap year is equal to 6/7.

Therefore, option (a) is correct.

Step-by-step explanation:

We know that, a non-leap year has 365 days in total and a year has 52 weeks in it. Hence there will be 52 Fridays for sure in a year.

Because, 52 weeks = $52 \times 7 = 364\; days .$

There will be in extra day in non-leap year as 365– 364 = 1

So, in a non-leap year, there will be 52 Fridays and one day will be left.

This one day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday.

Now we have total number of outcomes is 7 while the favorable outcomes are one.

The probability of getting 53 Fridays = 1 / 7.

The probability to exactly 52 Fridays = 1 - 1 / 7 = 6/7.

Therefore, the probability to have exactly 52 Fridays in a non -leap year

is 6/7.

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