Question

the probablity of A Solving a problem is 3/7 and B solve the prproblem 1/3 . what is the probablity that (1) at least one of them solve the problem ?​

Answer 1

Answer:

Step-by-step explanation:

P(atleast one of them solves the problem) = P( A solves the problem and B not) + P(B solves the problem and A not) + P(both solves the problem)

= (3/7)(1-(1/3)) + (1-(3/7))(1/3) + (3/7)(1/3)

= (3/7)(2/3) + (4/7)(1/3) + (3/7)(1/3)

= 6/21 + 4/21 + 3/21

= 13/21

Hope it helps

Answer 2

P(A)=3/7

P(B)=1/3

since A,B are independent events

P(A^B)=P(A).P(B)

=1/7

P(AUB)=P(A)+P(B)-P(A^B)

=(3/7)+(1/3)-(1/7)

= (2/7)+(1/3)

=13/21