Question

The Prodrect of a non-zero whole number and it's successor is always divisible by op:3 op :4 op:5 op:2

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Answer 1

Answer:

It is always divisible by 2

Step-by-step explanation:

Let the no. be 'x'

Then its successor is 'x+1'

Product = x(x+1) = x^2 + x

Case 1 : If x = 2n

x^2 + x = (2n)^2 + 2n = 4n^2 + 2n = 2(2n^2+n)

As 2 is its factor it is always divisible by 2

Case 2 : If x = 2n +1

x^2 + x = (2n+1)^2 + 2n = 4n^2 + 4n + 4 + 2n = 4n^2 + 6n + 4 = 2(2n^2 + 3n + 2)

As 2 is its factor it is always divisible by 2

So, In both the cases it is divisible by 2

So the product of a no. and its successor is always divisible by 2

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Answer 2

Answer:

2

Step-by-step explanation: