the product
0 Find
using
5
suitable
of (x + 3) (x + 3) by
identity
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0
Answer:
Step-by-step explanation:
(3x)2+52+2.3x.5 [∵(a+b)2=a2+b2+2ab]. =9x2+25+30x. (D)(x−1)(x−6)=x2−6x−x+6. =x2−7x+6.
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0
Answer:
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