The product and sum of object distance and focal length of a convex are -150 cm and -5 cm respectively. Find the image distance and nature of images
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Answer; as it was given that U+f= -5-----(i)
and
Uf=-150.....U=-150/f-----(ii)
then putting the value of equ^n 2in 1 we get f=10 cm and-15 cm
as it has told about convex lens so f will be positive f=10 cm then U=-15 cm
using the lens formula 1/v=1/f+1/U
=>1/v=1/10-1/15=5/150=1/30
so v=30 cm
nature of img; height of img is equal to the twice of height of obj.[obj dist is -1/2 of img dist]
magnification=-2
real and inverted
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