Math, asked by pubg40374, 8 months ago

The product and sum of the zeroes of the polynomial 2x2 – 2v2 x + 1 are respectively.​

Answers

Answered by abhi569
10

Answer:

1/2 & √2

Step-by-step explanation:

Polynomials written in form of k(x^2 - Sx + P), present S as sum of roots of and P as product of roots, for any constant.

In the above expression, our main concern was to make 1 as the coefficient of x^2.

Here,

→ 2x² - 2√2x + 1

→2(x² - √2x + 1/2)

Therefore, √2 = sum of roots

1/2 = product of roots.

Answered by guddupawar9389
0

Answer

10

5.0

Answer:

1/2 & √2

Step-by-step explanation:

Polynomials written in form of k(x^2 - Sx + P), present S as sum of roots of and P as product of roots, for any constant.

In the above expression, our main concern was to make 1 as the coefficient of x^2.

Here,

→ 2x² - 2√2x + 1

→2(x² -√2x + 1/2)

Therefore, √2 = sum of roots

1/2 = product of roots.

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