The product and sum of the zeroes of the polynomial 2x2 – 2v2 x + 1 are respectively.
Answers
Answered by
10
Answer:
1/2 & √2
Step-by-step explanation:
Polynomials written in form of k(x^2 - Sx + P), present S as sum of roots of and P as product of roots, for any constant.
In the above expression, our main concern was to make 1 as the coefficient of x^2.
Here,
→ 2x² - 2√2x + 1
→2(x² - √2x + 1/2)
Therefore, √2 = sum of roots
1/2 = product of roots.
Answered by
0
Answer
10
5.0
Answer:
1/2 & √2
Step-by-step explanation:
Polynomials written in form of k(x^2 - Sx + P), present S as sum of roots of and P as product of roots, for any constant.
In the above expression, our main concern was to make 1 as the coefficient of x^2.
Here,
→ 2x² - 2√2x + 1
→2(x² -√2x + 1/2)
Therefore, √2 = sum of roots
1/2 = product of roots.
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