Math, asked by kishordfunde, 1 year ago

the product denoting the numbers of pragatis age 2 years ago and 3 years hence is 84.find her present age​

Answers

Answered by arpitgoel284
10

Answer:

9

Step-by-step explanation:

let present age = x

2 year ago = x - 2

3 year hence = x + 3

( x - 2) ( x + 3 ) = 84

x square + 3x - 2x - 6 =84

x square + x - 90 = 0

by hit and trial method

x = 9

present age = 9

Answered by mathmagic1923
6

Answer:

The answer is 9

PLEASE MARK IT BRAINLIEST.

Step-by-step explanation:

Let the present age be x

Then,

Age 2 years ago = (x-2)

Age 3 years hence =(x+3)

Atq,

(x-2)*(x+3)=84

x^2+3x-2x-6=84

x^2+x=90

x^2+x-90=0

Now, We find the number which makes LHS = RHS

THE NUMBER WHICH SATISFYS IT IS 9.

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