Math, asked by soumya200710, 9 months ago

the product of 10 odd numbers and 3 even numbers​

Answers

Answered by shilpirishikanchan
0

Answer:

The product of the first n positive odd numbers is:

(2n)!2n⋅n!

Since gives n!≈2πn−−−√(n/e)n , that is approximately:

2–√(2n/e)n

To me this approximation is more interesting than whatever the actual value for n=10 happens to be in decimal (namely, 654729075 , when the approximation gives 657461211 less than 12% off).

Step-by-step explanation:

Please please please please make it brainlist

Answered by tuktuki8
0

Answer:

What is the product of the first 10 odd numbers?

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The product of the first n positive odd numbers is:

(2n)!2n⋅n!

Since gives n!≈2πn−−−√(n/e)n, that is approximately:

2–√(2n/e)n

To me this approximation is more interesting than whatever the actual value for n=10 happens to be in decimal (namely, 654729075, when the approximation gives 657461211 less than 12% off).

What is the product of the first 100 odd numbers?

What is the product of the first five odd numbers?

What is the product of odd numbers between 1 and 99?

Is there any formula for computing the product of the first 'N' odd/even numbers?

What is the product of the first 10000 odd numbers?

Γ(212)⋅210π√=210π√∫∞0x9.5e−x dx=∏k=110(2k−1)= 654,729,075

This answer is not a joke. Seeing how products of odd numbers appear in the Gamma function evaluated at half integers (or equivalently, in integrals of the type shown here) is a useful connection to make.

For confirmation that all three are the same number, see:

Step-by-step explanation:

please mark as brain list

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