The product of 2 conductive +ve integer is 306 we need to find in integers
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Let the 2 consecutive positive integers be ' x ' and ' x + 1 '
Therefore, according to the given condition,
x ( x + 1 ) = 306
x² + x = 306
x² + x - 306 = 0
x² -17x + 18x - 306 = 0
x ( x - 17 ) + 18 ( x - 17 ) = 0
( x -17 ) ( x + 18 ) =0
x - 17 = 0 or x +18 = 0
x = 17 or x = -18
Here, x is a positive integer and it cannot be negative
Therefore, x = -18 is unacceptable.
Therefore, x = 17 .
also, x + 1 = 17 + 1 = 18 .
Therefore, the 2 consecutive positive integers are 17 and 18
Therefore, according to the given condition,
x ( x + 1 ) = 306
x² + x = 306
x² + x - 306 = 0
x² -17x + 18x - 306 = 0
x ( x - 17 ) + 18 ( x - 17 ) = 0
( x -17 ) ( x + 18 ) =0
x - 17 = 0 or x +18 = 0
x = 17 or x = -18
Here, x is a positive integer and it cannot be negative
Therefore, x = -18 is unacceptable.
Therefore, x = 17 .
also, x + 1 = 17 + 1 = 18 .
Therefore, the 2 consecutive positive integers are 17 and 18
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