Question

the product of 2 consecutive multiple of 7 is 768.write statement in algebra​

Answer 1

Let two consecutive numbers be xx and x+7x+7

According to the question,

\Rightarrow⇒ x^2+(x+7)^2=637x

2

+(x+7)

2

=637

\Rightarrow⇒ x^2+x^2+14x+49=637x

2

+x

2

+14x+49=637

\Rightarrow⇒ 2x^2+14x+49-637=02x

2

+14x+49−637=0

\Rightarrow⇒ 2x^2+14x-588=02x

2

+14x−588=0

\Rightarrow⇒ 2(x^2+7x-294)=02(x

2

+7x−294)=0

\Rightarrow⇒ x^2+7x-294=0x

2

+7x−294=0

\Rightarrow⇒ x^2+21x-14x-294=0x

2

+21x−14x−294=0

\Rightarrow⇒ x(x+21)-14(x+21)=0x(x+21)−14(x+21)=0

\Rightarrow⇒ (x+21)(x-14)=0(x+21)(x−14)=0

\Rightarrow⇒ x+21=0x+21=0 and x-14=0x−14=0

\Rightarrow⇒ x=-21x=−21 and x=14x=14

\Rightarrow⇒ Here, one number is 1414

\Rightarrow⇒ Other, number =x+7=14+7=21=x+7=14+7=21

\Rightarrow⇒ The product of two multiple 14\times 21=29414×21=294

hope it helps

Mark as brainliest

Answer 2

Answer:

not knowing sorry....