Question

the product of 2 consecutive natural numbers is 56. solve this problem by using completing the square of quadratic equation. write the equation obtained after completing the square and also write the smaller of the 2 numbers. if you get the answer correct i shall mark you the brainiest

Answer 1

The algebra way

Let the first number be n

Then the second number is n+1

The product is n×(n+1)=56

⇒n2+n−56=0

Known: 7×8=56. However the equation's 56 is negative, so one of the 7 and 8 is negative.

The equation has +n so the larger of the two is positive. Giving:

(n−7)(n+8)=0

⇒n=+7  and n=−8

As a first number n=−8 is not logical so the first number is n=7

Thus the second number is 8.

Answer 2

Answer:

Second number is 8....m